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22w^2-37w=0
a = 22; b = -37; c = 0;
Δ = b2-4ac
Δ = -372-4·22·0
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-37}{2*22}=\frac{0}{44} =0 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+37}{2*22}=\frac{74}{44} =1+15/22 $
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